Trying to Calculate Initial Velocity and Final Velocity

AI Thread Summary
The discussion focuses on calculating initial and final velocities using the equation 1/2 mv^2 = kx^2. The initial velocity was calculated to be approximately 0.7071 m/s, but there are concerns about the accuracy of the spring constant and potential typos in the equation. Participants emphasize the need for more detailed information about the experiment, including the direction of the mass's release and the data collected. Clarifications on the spring's potential energy and compression values are also requested to ensure accurate calculations. Overall, the thread highlights the importance of precise data and clear communication in physics problem-solving.
rosephysics
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Homework Statement
Ball was released from a spring. I have the ball mass 0.15 kg, spring PE 0.15 J and spring compression 0.05 m. I have to find initial Velocity, initial KE, then initial momentum, final velocity, and final momentum.

I have data plots and I found the slope. (0.3860, 38.05) (0.5883, 38.05) Are the two points on the line.

I tried to calculate initial Velocity but I don't think I used the right formula.

This is all for a homework lab so I can't share the direct file/question. The lab is titled conservation of momentum.
Relevant Equations
I have to find initial Velocity, initial KE, then initial momentum, final velocity, and final momentum.
1/2 mv^2 kx^2
1.2(0.15)v^2 = 1/2 (3)(0.05)^2
0.075 v^2 = 0.00375
V^2 = 0 00375 / 0.075
V^2 = 0.05
Initial Velocity = 0.7071 m/s

I tried to calculate this one. I think for final velocity I should be using the slope? Any help would be appreciated thank you!
 
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If you cannot share the original file with the question, you need to say more about what you did. "Ball was released from a spring" does not say much to me. You mention that the spring was compressed, OK, but then what? Was the mass shot straight up, straight down or at angle? You mention data plots. What did you measure? What did you plot? Surely you can share the plots.
 
rosephysics said:
spring PE 0.15 J
How do you know?
rosephysics said:
1.2(0.15)v^2 = 1/2 (3)(0.05)^2
(Typo: 1/2 not 1.2)
Spring constant is 3N/m? That doesn’t match your compression and spring PE numbers.
 
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