Two Dice Toss: Outcomes & Plotting

In summary, when two dice are tossed, the sum of the dots observed on the dice forms the random variable \(X\) and the difference forms \(Y\). The possible outcomes of the random vector \((X, Y)\) are (2, 0), (3, -1), (3, 1), (4, -2), (4, 0), (4, 2), (5, -1), (5, 1), (6, 0), which can be plotted in the plane. There are 9 possible outcomes in total.
  • #1
Dustinsfl
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Two dice are tossed. The number of dots observed on the dice are added together to form the random variable \(X\) and also difference to form \(Y\). Determine the possible outcomes of the random vector \((X, Y)\) and plot them in the plane. How many possible outcomes are there?

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  • #2
:The possible outcomes of the random vector \((X, Y)\) are (2, 0), (3, -1), (3, 1), (4, -2), (4, 0), (4, 2), (5, -1), (5, 1), (6, 0). These outcomes can be plotted in the plane as shown below. There are 9 possible outcomes.\[\begin{array}{cc}\textbf{X} & \textbf{Y} \\2 & 0 \\3 & -1 \\3 & 1 \\4 & -2 \\4 & 0 \\4 & 2 \\5 & -1 \\5 & 1 \\6 & 0 \end{array}\]\begin{tikzpicture}\draw[->] (-0.5, 0)--(6.5, 0);\draw[->] (0, -2.5)--(0, 2.5);\draw[thick] (2, 0)--(3, -1)--(3, 1)--(4, -2)--(4, 0)--(4, 2)--(5, -1)--(5, 1)--(6, 0)--(2, 0);\fill[black] (2, 0) circle (2pt);\fill[black] (3, -1) circle (2pt);\fill[black] (3, 1) circle (2pt);\fill[black] (4, -2) circle (2pt);\fill[black] (4, 0) circle (2pt);\fill[black] (4, 2) circle (2pt);\fill[black] (5, -1) circle (2pt);\fill[black] (5, 1) circle (2pt);\fill[black] (6, 0) circle (2pt);\node at (-0.5, 0) {0};\node at (6.5, 0) {6};\node at (0, -2.5) {-2};\node at (0, 2.5) {2};\end{tikzpicture}
 

Related to Two Dice Toss: Outcomes & Plotting

1. What is the probability of rolling a sum of 7 on a pair of fair dice?

The probability of rolling a sum of 7 on a pair of fair dice is 1/6 or approximately 16.67%. This is because there are six possible outcomes when rolling two dice (1+6, 2+5, 3+4, 4+3, 5+2, 6+1) and only one of those outcomes results in a sum of 7 (6+1).

2. How can I calculate the probability of rolling a sum of 9 or higher?

To calculate the probability of rolling a sum of 9 or higher, you can first determine the total number of possible outcomes (36) and then subtract the number of outcomes that result in a sum of 8 or lower (20). This leaves 16 outcomes that result in a sum of 9 or higher. Therefore, the probability is 16/36 or approximately 44.44%.

3. Can the outcomes of a two dice toss be represented on a graph?

Yes, the outcomes of a two dice toss can be represented on a graph. A common way to plot the outcomes is to have the x-axis represent the sum of the two dice and the y-axis represent the frequency or number of times that sum was rolled. This results in a bell-shaped curve known as a normal distribution.

4. How does the number of dice affect the outcomes and probabilities?

The number of dice can greatly affect the outcomes and probabilities of a roll. For example, rolling three dice will result in a larger range of possible outcomes compared to rolling two dice. Additionally, the probabilities for each outcome will change as the number of dice increases or decreases.

5. What is the difference between theoretical probability and experimental probability in a two dice toss?

Theoretical probability is the predicted probability of a certain outcome based on mathematical calculations. In a two dice toss, this would be determined by dividing the number of desired outcomes by the total number of possible outcomes. Experimental probability, on the other hand, is the observed probability based on actual results from a series of trials. In other words, it is the likelihood of a certain outcome based on real-world data.

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