Understanding Isothermal Processes

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In summary, when discussing the isothermal process and the first law of thermodynamics, it is noted that as ΔU = 0, Q = -W. This means that when heat enters the system, all energy is converted into work, which the gas does on the surroundings. However, it is questioned how the molecules can exert more force on the wall without a change in their kinetic energy. It is explained that when a gas is heated, the molecules do gain kinetic energy, but they also lose it when pushing the piston.
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bjgawp
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I've gone through a some of our textbooks but none of them effectively explains this process clearly. For the isothermal process, according to the first law of thermodynamics, ΔU = 0, indicating that Q = -W. So if heat flows into the system, all the energy put in is converted to work which the gas does on the surroundings. However, microscopically, how do the molecules exert more force on the wall (i.e. more pressure) without a change in their kinetic energy (i.e. their internal energy)? Taking a container with a movable piston, if the gas moves the piston by work - doesn't that mean that the molecules have gained more kinetic energy to move it?

Thanks in advance!
 
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Yes, when you heat the gas the molecules gain kinetic energy, and they lose it pushing the piston.
 
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I can provide a response to your question regarding isothermal processes. First, let's define what an isothermal process is. It is a thermodynamic process where the temperature of a system remains constant throughout the process. This means that the internal energy of the system remains unchanged, as you have correctly stated. In this case, the first law of thermodynamics tells us that the change in internal energy (ΔU) is equal to the heat flow (Q) into the system minus the work (W) done by the system. In an isothermal process, since ΔU = 0, this means that Q = -W.

Now, let's address your question about how the molecules exert more force on the wall (increased pressure) without a change in their kinetic energy. This can be explained by looking at the microscopic level of the gas molecules. In an isothermal process, the temperature remains constant, but this does not mean that the individual molecules do not have different velocities (kinetic energies). Some molecules may have higher velocities while others may have lower velocities, but on average, the temperature remains constant. So, when the gas molecules collide with the walls of the container, they transfer their momentum to the walls, resulting in an increase in pressure. This does not necessarily mean that all the molecules have gained more kinetic energy, but rather that the overall average kinetic energy remains constant.

In the case of a movable piston, the work done by the gas on the piston is due to the transfer of kinetic energy from the gas molecules to the piston. This transfer of energy is a result of the collisions between the gas molecules and the piston. So, in this scenario, the molecules are not gaining more kinetic energy, but rather transferring their existing kinetic energy to the piston to do work.

I hope this explanation helps to clarify your understanding of isothermal processes. It is important to remember that at the microscopic level, there is a constant exchange of energy between the gas molecules and their surroundings, but at the macroscopic level, the temperature remains constant. This is what makes isothermal processes unique and important in thermodynamics.
 

Related to Understanding Isothermal Processes

1. What is an isothermal process?

An isothermal process is a type of thermodynamic process in which the temperature of a system remains constant throughout the process. This means that the system's internal energy remains constant, as heat is added or removed to maintain the temperature.

2. How does an isothermal process differ from other thermodynamic processes?

An isothermal process differs from other thermodynamic processes, such as adiabatic or isobaric processes, in that it maintains a constant temperature rather than a constant pressure or volume. This makes it useful for studying the behavior of gases and other systems that are in thermal equilibrium with their surroundings.

3. What is the equation for calculating work done in an isothermal process?

The equation for calculating work done in an isothermal process is W = nRT ln(V2/V1), where W is the work done, n is the number of moles of gas, R is the gas constant, T is the temperature in Kelvin, and V2 and V1 are the initial and final volumes of the gas.

4. How is an isothermal process represented on a pressure-volume graph?

On a pressure-volume graph, an isothermal process is represented by a horizontal line. This is because the temperature remains constant, so the pressure and volume are inversely proportional according to Boyle's Law.

5. What are some real-world examples of isothermal processes?

Some real-world examples of isothermal processes include the melting of ice at 0 degrees Celsius, the boiling of water at 100 degrees Celsius, and the expansion of a gas in a refrigerator. It is also used in industrial processes such as refrigeration, chemical reactions, and power generation.

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