- #1
totallyclone
- 54
- 0
Homework Statement
A bushman wants to hunt down a kangaroo so he uses a vine which is 2.0m long with a rock tied to the end of it. The bushman holds the other hand above his head which is 2.0m above the ground. The kangaroo observes that when the angle with the vine and vertical reaches 60°, the vine breaks. So, what's the minimum distance for the rock not to hit the kangaroo?
θ = 60°
vine length = 2.0m
Y-component initial = 2.0m
Y-component final = 0.0m
Homework Equations
ac = V2/r
The Attempt at a Solution
I drew a diagram of it and put in the data I know so far.
I thought of this question for a bit and I feel like this question requires the concept of projectile motion (when the vine breaks and the rock flies to the kangaroo) and centripetal forces (because the rock is being spun tied to a vine).
The thing is, if I try to find acceleration here, it would be the perpendicular acceleration but when the vine breaks, wouldn't the acceleration that would be affecting the rock by then is a parallel acceleration because it does not go in a circle anymore?
Last edited: