Using corrcted value for Hardy Cross method?

In summary, the conversation is discussing whether or not to use the corrected value for a junction that divides two loops in a Hardy Cross problem. The first example suggests using the corrected value, while the second example shows the author using the corrected value. It is unclear which is the correct approach.
  • #1
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Homework Statement


i have several example of hardy cross problem involve 2 loops , for the junction that divide 2 loops , is it necessary to use the corrected value for the junction on second loop for the first trial ? or just use the initial assumption will do ?
http://nptel.ac.in/courses/112104118/lecture-36/hyperlink/examp_36_1.htm
using this example , the BD is the junction that divide 2 loops , should we use the corrected value 0.8 -(-0.46) =1.26 or stick to the original assumption (0.8) just like the author ?

in the second example here , the author use the corrected value (0.01731) for junction BE in the second loop instead of 0.0
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Homework Equations

The Attempt at a Solution


i think in the first example , we should use he corrected value 0.8 -(-0.46) =1.26 instead of 0.8
 
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  • #2
which is correct ?
 
  • #3
which is correct ? with or without correction ?
 
  • #4
anybody can answer ?>
 
  • #5
bump
 

Related to Using corrcted value for Hardy Cross method?

1. What is the Hardy Cross method?

The Hardy Cross method is an iterative technique used to solve for flow in a network of pipes. It involves balancing the flow and head losses at each node in the network to determine the flow rates in each pipe.

2. Why is it important to use corrected values in the Hardy Cross method?

Using corrected values in the Hardy Cross method ensures that the solution obtained is accurate and reflects the real-world conditions of the network. This is especially important in systems with large variations in pipe sizes and flow rates.

3. How are corrected values determined in the Hardy Cross method?

Corrected values in the Hardy Cross method are determined by incorporating the effect of minor head losses, such as bends and fittings, into the calculations. These losses are calculated based on empirical equations and added to the overall head loss at each node in the network.

4. What are the benefits of using corrected values in the Hardy Cross method?

Using corrected values in the Hardy Cross method improves the accuracy of the solution and ensures that the flow rates and head losses calculated are closer to the actual values in the real system. This can lead to better design and more efficient operation of the network.

5. Are there any limitations to using corrected values in the Hardy Cross method?

Corrected values in the Hardy Cross method are based on empirical equations and may not accurately represent the actual minor head losses in the system. Additionally, the method assumes steady-state flow and may not be suitable for networks with unsteady flow conditions.

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