Variation of vapor pressure with temperature

[utkarshakash]

Homework Statement

The following link shows the variation of vapor pressure with temperature. In which way the data should be plotted to obtain a straight line?

http://www.chem.purdue.edu/gchelp/liquids/vpress.html

The Attempt at a Solution

For this, I need to know exactly the mathematical relationship which I can't seem to find anywhere. Anyways, my immediate guess would be that the graph is an exponential function. So plotting the graph of lnP vs T would give me a straight line but the correct answer is lnP vs 1/T. I'm sure I'm missing something here.

 

[Chestermiller]

Are you familiar with the Clausius Clapeyron equation?

Chet

 

[Yanick]

This is the one component, two phase (solid-gas, liquid-gas) "version" of the Clausius-Clayperon equation.

 

[utkarshakash]

Thanks to both of you.

 

[DeeNos]

Can you help?

As a scientist, it is important to understand the underlying principles and equations governing the relationship between vapor pressure and temperature. In this case, the Clausius-Clapeyron equation is the fundamental equation that relates vapor pressure to temperature. This equation is based on the thermodynamic principles of phase equilibrium and can be written as ln(P) = -ΔHvap/R(1/T) + C, where P is vapor pressure, T is temperature, ΔHvap is the enthalpy of vaporization, R is the gas constant, and C is a constant.

Based on this equation, the correct way to plot the data is ln(P) versus 1/T, which would result in a linear relationship. This is because the Clausius-Clapeyron equation is an exponential function, and taking the natural logarithm of both sides results in a linear relationship between ln(P) and 1/T.

Therefore, to obtain a straight line when plotting vapor pressure versus temperature, it is important to use the correct mathematical relationship based on the underlying principles and equations. This ensures accurate and meaningful interpretation of the data.