- #1
ZedCar
- 354
- 1
I obtained the following from a book.
Question is:
Periodic Sawtooth described by the following;
f(x) = x/2∏ for 0<x<2∏
f(x+2∏) = f(x) for -∞<x<+∞
The solution is:
If x = 0
y = 0
If x = 2∏
y = 2∏/2∏ = 1
If x = 4∏
y = f(2∏+2∏) = 2∏ = 1
Can anyone explain to me why when x = 4∏ y = 1 ? I'm not clear on that bit.
I would just think if you're putting x = 4∏ into the 2nd equation in the question you would get y = f(4∏+4∏) = f(8∏)
I know a full rotation is 2 ∏, so I can see how 8∏ would be the same as 2∏, but then how did they go from 2∏ to 1 in the part above which I have emboldened?
Thank you
Question is:
Periodic Sawtooth described by the following;
f(x) = x/2∏ for 0<x<2∏
f(x+2∏) = f(x) for -∞<x<+∞
The solution is:
If x = 0
y = 0
If x = 2∏
y = 2∏/2∏ = 1
If x = 4∏
y = f(2∏+2∏) = 2∏ = 1
Can anyone explain to me why when x = 4∏ y = 1 ? I'm not clear on that bit.
I would just think if you're putting x = 4∏ into the 2nd equation in the question you would get y = f(4∏+4∏) = f(8∏)
I know a full rotation is 2 ∏, so I can see how 8∏ would be the same as 2∏, but then how did they go from 2∏ to 1 in the part above which I have emboldened?
Thank you