- #1
Addez123
- 199
- 21
- Homework Statement
- X is the amount of calls a phone will recieve each day.
$$X \in Po(u)$$
For n days the following amount of calls were recorded
115, 82, 108, 106, 118, 87, 99, 92
1. Calculate μ.
2. Estimate the mean error of μ.
- Relevant Equations
- $$μ* = (x1 + x2 + x3..+xn)/n$$
$$D(μ*) = \sigma/\sqrt n$$
$$\sigma ~= s$$
$$s^2 = \frac 1 {n-1} * \sum_{j=1}^n {x_j - μ*}$$
1. μ* is easily calculated to be 100.88, textbook confirms its 100.9.
Its just the mean of all those values.
2. To estimate mean error I first calculate s^2, which is:
$$s^2 = 1/7 * ((115 - 100.9)^2 + (82 - 100.9)^2 ... + (92-100.9)^2) = 1200.88$$
$$s = \sqrt s = 34.65$$
Then I use this formula except instead of sigma I use s
$$D(μ*) = \sigma/\sqrt n ~= s/\sqrt n = 34.65/\sqrt 8 = 12.25$$
The book says the answer is 3.55, which first of all doesn't feel resonable either.
Shouldnt most numbers (66%) lies within the scope of μ +- s? (88.65 - 113.15, if s = 12.25)?
As that is the definition of a standard deviation.
Its just the mean of all those values.
2. To estimate mean error I first calculate s^2, which is:
$$s^2 = 1/7 * ((115 - 100.9)^2 + (82 - 100.9)^2 ... + (92-100.9)^2) = 1200.88$$
$$s = \sqrt s = 34.65$$
Then I use this formula except instead of sigma I use s
$$D(μ*) = \sigma/\sqrt n ~= s/\sqrt n = 34.65/\sqrt 8 = 12.25$$
The book says the answer is 3.55, which first of all doesn't feel resonable either.
Shouldnt most numbers (66%) lies within the scope of μ +- s? (88.65 - 113.15, if s = 12.25)?
As that is the definition of a standard deviation.