What is the decay constant of tritium?

In summary, tritium is the key component in increasing the power of fission bombs and promoting fission in basic atom bombs or reactors. While plutonium is a stable material, tritium has a much faster decay rate of 5.5% per year. The half-life of tritium can be found using the equation t_{1/2} = \dfrac{\ln(2)}{r}.
  • #1
tcking3
3
0
"Tritium is the basic fuel of hydrogen bombs and is used to increase the power for fission bombs . . . In a basic atom bomb (or reactor), plutonium atoms are split, or fissioned, to release energy, but the fission can be promoted with a small amount of tritium because it has two extra atom-splitting neutrons. Plutonium is a relatively stable material, and its natural decay is not a major factor in bomb maintenance. Tritium, however, decays at a rate of 5.5percent a year."

What is the half life of tritium?

I think you would need to set up an A(t)= Ae^rt equation but I am having trouble pinpointing what to put in.
 
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  • #2
You could state:

\(\displaystyle A(t)=A_0e^{-kt}\)

where $t$ is measured in years.

Now, using the given information, what is $A(1)$?
 
  • #3
tcking3 said:
"Tritium is the basic fuel of hydrogen bombs and is used to increase the power for fission bombs . . . In a basic atom bomb (or reactor), plutonium atoms are split, or fissioned, to release energy, but the fission can be promoted with a small amount of tritium because it has two extra atom-splitting neutrons. Plutonium is a relatively stable material, and its natural decay is not a major factor in bomb maintenance. Tritium, however, decays at a rate of 5.5percent a year."

What is the half life of tritium?

I think you would need to set up an A(t)= Ae^rt equation but I am having trouble pinpointing what to put in.

Generally exponential decay is written as \(\displaystyle A(t) = Ae^{-rt}\) although all this does is change the sign of \(\displaystyle r\).To find the decay constant, \(\displaystyle r\) find out what happens after 1 year (ie: when \(\displaystyle t = 1\))Half-life and the decay constant are linked by the equation \(\displaystyle t_{1/2} = \dfrac{\ln(2)}{r}\) (you can show this from your original equation)
 

1. What is a Half Life Diffeq problem?

A Half Life Diffeq problem is a mathematical equation used to model the rate at which a substance decays or decreases over time. This type of problem is often used in science and engineering to analyze the behavior of radioactive materials, chemical reactions, and other natural phenomena.

2. How do you solve a Half Life Diffeq problem?

To solve a Half Life Diffeq problem, you need to use a differential equation that describes the rate of change of the substance over time. This equation can then be solved using various mathematical techniques, such as separation of variables, substitution, or integration.

3. What information is needed to solve a Half Life Diffeq problem?

To solve a Half Life Diffeq problem, you need to know the initial amount of the substance, the rate at which it decays, and the time period over which the decay occurs. This information can be obtained from experimental data or given in the problem statement.

4. Can a Half Life Diffeq problem be applied to real-life situations?

Yes, a Half Life Diffeq problem can be applied to many real-life situations, such as radioactive decay in nuclear reactors, carbon dating of artifacts, and drug metabolism in the human body. It is a useful tool for understanding and predicting the behavior of natural processes.

5. Are there any limitations to using a Half Life Diffeq problem?

While a Half Life Diffeq problem can provide valuable insights and predictions, it does have some limitations. It assumes that the decay rate of the substance is constant, which may not always be the case in real-life situations. Additionally, it may not take into account external factors that can affect the decay process, such as temperature changes or the presence of other substances.

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