What is the minimum depth of snow needed to stop a paratrooper safely?

In summary, the conversation discusses a paratrooper falling from an airplane without being able to open his chute. The parameters given include the distance fallen, terminal speed, mass, and the force on him from the snow. The questions asked are for the minimum depth of snow needed to stop him safely, and the magnitude of the impulse on him from the snow. The responder advises the asker to review the rules and show their understanding of the problem by listing relevant equations and providing their attempts before seeking further help.
  • #1
patelkey
16
0

Homework Statement



A paratrooper fell 375 m from an airplane without being able to open his chute. Assume that his speed at impact was 52 m/s (terminal speed), that his mass (including gear) was 85 kg, and that the force on him from the snow was at the survivable limit of 1.2 multiplied by 105 N.

a.) What is the minimum depth of snow that would have stopped him safely?

b.)What is the magnitude of the impulse on him from the snow?

Homework Equations





The Attempt at a Solution

 
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  • #2
Hi patelkey, welcome to PF. Please go through the PF rules. According that you have to show how much you know about the problem. You have to find out the relevant equations to solve the given problem. You have to your attempts. Still you are not getting the answer, we will help you.
So first of write down the relevant equations.
 
  • #3


a.) To determine the minimum depth of snow needed to stop the paratrooper safely, we can use the equation for kinetic energy, KE = 1/2mv^2, where m is the mass of the paratrooper and v is his speed at impact. Since the force of the snow on the paratrooper is equal to the change in momentum, we can also use the equation FΔt = mΔv, where F is the force of the snow, Δt is the time interval of impact, and Δv is the change in velocity. By setting these two equations equal to each other, we can solve for the minimum depth of snow, d, using the equation d = (mΔv)/(2F). Plugging in the given values, we get d = (85 kg * 52 m/s)/(2 * 1.2 * 105 N) = 1.48 m. Therefore, the minimum depth of snow needed to stop the paratrooper safely is approximately 1.48 meters.

b.) The impulse on the paratrooper from the snow can be calculated using the equation Impulse = FΔt, where F is the force of the snow and Δt is the time interval of impact. Plugging in the given values, we get Impulse = (1.2 * 105 N)(Δt). Since we do not know the exact time interval of impact, we cannot calculate the exact magnitude of the impulse. However, we can say that the magnitude of the impulse would be equal to or less than 1.2 * 105 N.
 

1. What is a collision?

A collision is an event in which two or more objects come into contact with each other and exchange energy or momentum.

2. What is impulse?

Impulse is the change in momentum of an object as a result of a force acting on it for a certain amount of time.

3. How do you calculate impulse?

Impulse can be calculated by multiplying the force applied to an object by the time duration of the force.

4. What is the difference between elastic and inelastic collisions?

In an elastic collision, both kinetic energy and momentum are conserved, while in an inelastic collision, only momentum is conserved but kinetic energy is lost.

5. How do you use the laws of conservation of momentum and energy to solve collision problems?

The laws of conservation of momentum and energy can be used to set up equations and solve for unknown variables in a collision problem. These laws state that the total momentum and energy of a system before a collision is equal to the total momentum and energy after the collision.

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