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mathdad
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Find the vertical asymptote of f(x) = (5 - x^2)/(x - 3). I need the steps not the solution.
RTCNTC said:Find the vertical asymptote of f(x) = (5 - x^2)/(x - 3). I need the steps not the solution.
skeeter said:Vertical asymptote is x = 3 ... why?
tkhunny said:$g(x) = \dfrac{9-x^{2}}{x-3}$
NOT a Vertical Asymptote. Why?
RTCNTC said:tkhunny said:$g(x) = \dfrac{9-x^{2}}{x-3}$
NOT a Vertical Asymptote. Why?
According to Skeeter, x = 3 is a vertical asymptote.
skeeter said:Where did I say that?
I said $f(x) = \dfrac{5 - x^2}{x-3}$ had the vertical asymptote at $x=3$, not the function cited by tkhunny.
A vertical asymptote is a vertical line on a graph that represents a value or point where the function becomes undefined or approaches infinity.
To find the vertical asymptote of a function, you must set the denominator of the function equal to zero and solve for the variable. The resulting value is the x-coordinate of the vertical asymptote.
No, a vertical asymptote cannot intersect with the graph of a function because the function becomes undefined at that point and the graph cannot be drawn.
A vertical asymptote represents a value where the function becomes undefined, while a horizontal asymptote represents a value that the function approaches as x approaches infinity or negative infinity.
Yes, a function can have multiple vertical asymptotes if the denominator of the function has more than one value that makes it equal to zero.