- #1
PurelyPhysical
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Why are the units of force used when applying coulombs law (N-M^2)/(C^2)? This is actually a three part question.
1. Why are the units of the permitivity constant (C^2)/(N-M^2)?
2. Why do Q1 and Q2 not contribute to the final units? Each charge is measured in coulombs, but those units don't reflect in the final units.
3. Units of force are Newtons. Why then can we say that coulombs law equals force? What's going on with the other units that makes it so that we can still refer to it as a force?
1. Why are the units of the permitivity constant (C^2)/(N-M^2)?
2. Why do Q1 and Q2 not contribute to the final units? Each charge is measured in coulombs, but those units don't reflect in the final units.
3. Units of force are Newtons. Why then can we say that coulombs law equals force? What's going on with the other units that makes it so that we can still refer to it as a force?