- #1
greypilgrim
- 515
- 36
Hi.
If a plate capacitor is charged with some charge ##Q##, then there's a voltage ##U=Q/C## between the plates. The electric field between the plates is ##E=U/d##.
Voltage is path independent, if I connect the plates with a cable of length ##l\gg d## the voltage across the cable is the same. The electric field along the cable will probably not be constant, but the mean field ##U/l## is much smaller than the field between the capacitor plates. So how can the force directing the charges through the cable be larger than the force from the other plate holding them back?
If a plate capacitor is charged with some charge ##Q##, then there's a voltage ##U=Q/C## between the plates. The electric field between the plates is ##E=U/d##.
Voltage is path independent, if I connect the plates with a cable of length ##l\gg d## the voltage across the cable is the same. The electric field along the cable will probably not be constant, but the mean field ##U/l## is much smaller than the field between the capacitor plates. So how can the force directing the charges through the cable be larger than the force from the other plate holding them back?