Why do 2 d not decay into alpha particle and neutral pion?

In summary, the reaction dd → απ0 has never been observed because it violates the conservation of mass. While energy can be conserved, the resulting particles have a combined mass that is greater than the initial state, making this reaction impossible. Particle colliders are able to produce heavier particles by colliding particles with enough kinetic energy.
  • #1
MxwllsPersuasns
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Homework Statement



The reaction dd → απ0 (where α is the Helium-4 nucleus and d denotes the deuteron) has never been observed. Why?

Homework Equations

The Attempt at a Solution


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So I checked first the masses to make sure energy/momentum are conserved and found out that mass of 2d is 3751.2 MeV while the decay products have a combined mass of 3862.27 which is greater than the initial state and thus violates conservation of mass. Could this possibly be the case? It just seems simple and we're currently studying topics such as isospin and parity and so I had checked things like charge and baryon number conservation and they seemed alright so I figured I might ask here. Thanks guys!
 
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  • #2
MxwllsPersuasns said:
and thus violates conservation of mass
Mass is not conserved. Energy is conserved but you could collide two particles with enough kinetic energy to make heavier particles. This is what particle colliders do.
 

1. Why do we observe 2 d not decaying into alpha particle and neutral pion?

This is because the decay of 2 d into alpha particle and neutral pion violates conservation of charge and baryon number. In this decay, the initial 2 d nucleus has a total charge of +2 and a baryon number of 2, while the final products have a total charge of +0 and a baryon number of 2. This violates the fundamental principle of conservation of charge and baryon number in nuclear interactions.

2. Is it possible for 2 d to decay into alpha particle and neutral pion?

No, it is not possible for 2 d to decay into alpha particle and neutral pion. As mentioned before, this decay violates conservation of charge and baryon number. In addition, the energy and momentum conservation laws also prevent this decay from occurring.

3. What is the most common decay mode for 2 d?

The most common decay mode for 2 d is the beta decay, where a neutron in the nucleus transforms into a proton, releasing an electron and an antineutrino. This results in the formation of a new nucleus with a higher atomic number and the release of energy.

4. Can 2 d decay into other particles besides the alpha particle and neutral pion?

Yes, 2 d can decay into other particles besides the alpha particle and neutral pion. Some possible decay modes include the emission of a proton or a deuteron, or the formation of a triton or helium-3 nucleus.

5. What other factors can affect the decay of 2 d?

The decay of 2 d can also be influenced by the nuclear structure and composition of the nucleus, as well as external factors such as temperature, pressure, and the presence of other particles. The probability of different decay modes can also vary depending on these factors.

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