Why do bound systems have less rest mass than the sum of its parts?

In summary: However, this is not always reliable as some particles (like photons) don't have an obvious impact on the motion of the box.
  • #1
dimwatt
8
0
Hi PF. This a fact well aware to just about anyone that has had even basic chemistry, but I'm having a hard time coming to an understanding as to why this must be true. So why?

Also, if I knew that some box contained, say, a proton and an electron, could I ever know whether or not, inside the box, the proton and the electron are in a bound state (hydrogen, as opposed to just two free particles) without puncturing or tampering with the boundaries of the box?
 
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  • #2
When the parts come together energy is released. That energy is called binding energy. To pull them apart the same amount of energy must now be provided. If the energy is not provided, the parts can't move apart - they are bound. By Einstein's relation E=mc2 the energy lost in the binding process corresponds to an amount of lost mass - called the mass deficit. Therefore the bound system contains less mass than the sum of its parts.
 
  • #3
dimwatt said:
Also, if I knew that some box contained, say, a proton and an electron, could I ever know whether or not, inside the box, the proton and the electron are in a bound state (hydrogen, as opposed to just two free particles) without puncturing or tampering with the boundaries of the box?

Yes, you could put the box on a scale and measure its mass. The hydrogen is lighter than the sum of the masses of the proton and electron.
 
  • #4
dauto said:
Yes, you could put the box on a scale and measure its mass. The hydrogen is lighter than the sum of the masses of the proton and electron.

True but whether or not the particles "came together" no energy escaped the box, so it would have the same mass. One way we could tell is by opening the box and finding out if it weighs less than it did before opening, in which case the binding energy escaped in the form of heat or radiation or something like that. But I'm asking if there is anyway to discern between hydrogen and proton+electron (free) without disturbing the closed system.
 
  • #5
dimwatt said:
True but whether or not the particles "came together" no energy escaped the box, so it would have the same mass. One way we could tell is by opening the box and finding out if it weighs less than it did before opening, in which case the binding energy escaped in the form of heat or radiation or something like that. But I'm asking if there is anyway to discern between hydrogen and proton+electron (free) without disturbing the closed system.

It's really hard to construct such an ideally closed system, but if you could then you are right: the mass of the box plus its contents would be the same whether the particles are bound (there's a hydrogen atom and some energy in the form of light/heat in the box) or unbound (there's a proton and an electron and the same energy in the form of an electrical field between them in the box).

There are other ways, in principle, of distinguishing the two cases; for example, the temperature of the box will be different; the electrical field outside the box will be different. However, they all depend, one way or another, on the box not being a perfect ideally closed system.
 
  • #6
dimwatt said:
True but whether or not the particles "came together" no energy escaped the box, so it would have the same mass. One way we could tell is by opening the box and finding out if it weighs less than it did before opening, in which case the binding energy escaped in the form of heat or radiation or something like that. But I'm asking if there is anyway to discern between hydrogen and proton+electron (free) without disturbing the closed system.

You could look for the recoil of the box every time some particle inside if bounces off the walls and infer what kind of particles are inside
 

1. Why do bound systems have less rest mass than the sum of its parts?

Bound systems, such as atoms and molecules, have less rest mass than the sum of its individual components due to the release of energy during the binding process. This energy is known as binding energy and it is a result of the strong nuclear force that holds the particles together. This energy is equivalent to the difference in mass between the bound system and its individual parts, according to Einstein's famous equation E=mc2.

2. How does the strong nuclear force contribute to the decrease in rest mass of bound systems?

The strong nuclear force is a fundamental force that exists between particles within the nucleus of an atom. This force is responsible for binding protons and neutrons together, forming the nucleus of an atom. As particles are bound together, they release energy, which results in a decrease in the overall rest mass of the system.

3. Can the binding energy of a bound system be converted back into mass?

Yes, the binding energy of a bound system can be converted back into mass. This is demonstrated in nuclear reactions, where the binding energy of atoms can be released in the form of nuclear energy. This energy can then be converted into mass, according to Einstein's equation.

4. Are there any exceptions to the rule that bound systems have less rest mass than the sum of its parts?

Yes, there are certain cases where bound systems may have a greater rest mass than the sum of its individual components. This is observed in particles known as hadrons, which are composed of quarks held together by the strong nuclear force. The mass of these particles is actually greater than the sum of the masses of its constituent quarks.

5. How does the decrease in rest mass affect the stability of bound systems?

The decrease in rest mass due to binding energy contributes to the stability of bound systems. This is because the release of energy during the binding process makes the system more energetically favorable and less likely to break apart. This is why bound systems, such as atoms and molecules, are able to exist in a relatively stable state.

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