Why Does Changing Magnetic Field Direction Affect Current in a Wire Loop?

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The discussion centers on calculating the current through a resistor in a wire loop subjected to a changing magnetic field. The initial magnetic field is 0.75 T, which is reversed to 0.35 T over 0.45 seconds, with the loop area being 0.32 m². The calculated electromotive force (emf) is 0.284 V, leading to a current of 0.019 A through a 15-ohm resistor. However, this answer is incorrect, as the expected current is 0.052 A. The error is attributed to an incorrect computation of the change in the magnetic field.
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Homework Statement


A loop of wire of aream 0.32m^2 is palced in a 0.75 T magnetic field. The magnetic field is changed to 0.35 T in the opposite direction in 0.45 s . What is the magnitude of the current through the 15 ohm resistor.


Homework Equations


emf = -N (flux / time)


The Attempt at a Solution



emf = (-1) [(.35T)(.32m^2)-(.75T)(.32m^2)]/(.45s)
emf = .284 V
V = IR
I = .284 V / 15ohm
I = .019 A

.019 is the wrong answer in the multiple choice
the correct answer is supposed to be 0.052 A

Thanks
 
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Destrio said:

Homework Statement


A loop of wire of aream 0.32m^2 is palced in a 0.75 T magnetic field. The magnetic field is changed to 0.35 T in the opposite direction in 0.45 s . What is the magnitude of the current through the 15 ohm resistor.


Homework Equations


emf = -N (flux / time)


The Attempt at a Solution



emf = (-1) [(.35T)(.32m^2)-(.75T)(.32m^2)]/(.45s)
emf = .284 V
V = IR
I = .284 V / 15ohm
I = .019 A

.019 is the wrong answer in the multiple choice
the correct answer is supposed to be 0.052 A

Thanks

Looks like you have not computed the change in field correctly.
 
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