- #1
bsodmike
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I was reading a text, describing the following disintegration:
[itex]^{234}_{90}Th\xrightarrow{}~^{0}_{-1}e+~^{234}_{91}Pa[/itex]
However, I prefer to understand it as,
[tex]^{234}_{90}Th\xrightarrow{}~e^{-}+~^{234}_{91}Pa[/tex]
Of course, the above two equations are missing out the antineutrino. Could someone please enlighten me why,
[tex]e^{-}\equiv~^{0}_{-1}e[/tex]
Am I supposed to read it as, p+n =0 but it contains a 'negative' proton number, i.e. a negative proton = an electron (although an electron has a mass of 1/1840 of that of a proton)
Cheers,
Mike.
[itex]^{234}_{90}Th\xrightarrow{}~^{0}_{-1}e+~^{234}_{91}Pa[/itex]
However, I prefer to understand it as,
[tex]^{234}_{90}Th\xrightarrow{}~e^{-}+~^{234}_{91}Pa[/tex]
Of course, the above two equations are missing out the antineutrino. Could someone please enlighten me why,
[tex]e^{-}\equiv~^{0}_{-1}e[/tex]
Am I supposed to read it as, p+n =0 but it contains a 'negative' proton number, i.e. a negative proton = an electron (although an electron has a mass of 1/1840 of that of a proton)
Cheers,
Mike.
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