Why is there no odd-even staggering for electronic binding energies?

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In summary, unpaired electrons are more reactive because they don't have the stability that paired electrons do.
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scope
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hi,

I am wondering why even numbers of protons, or neutrons, or electrons, are more stable that odd numbers?

i have read this on wikipedia:

http://en.wikipedia.org/wiki/Oddo-Harkins_rule

" In elements with even atomic numbers, protons are paired, with each member of the pair offsetting the spin of the other, enhancing stability "

the same principle applies for electrons?, so I was wondering what is the cause for this? I believe this is related to magnetic moment that leads to a magnetic attraction, or i am wrong?
please reply!
 
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  • #2
It applies to protons, and it also applies to neutrons, but it doesn't apply to electrons. It arises from the short-range, attractive nature of the nuclear force. Since the force between electrons is long-range and repulsive, you don't get the same effect.

The basic idea is that when you have a short-range, attractive force between, say, two neutrons, stability is optimized when the two wavefunctions are the same except that one is time-reversed compared to the other. Classically, this would be like having the two neutrons occupying the same orbit, but going around in opposite directions. Because the orbital planes are lined up, you maximize the overlap between the two wavefunctions, which means you're maximizing the binding.
 
  • #3
then why unpaired electrons are more reactive than paired electrons? this seems to mean that they are less stable
 
  • #4
scope said:
then why unpaired electrons are more reactive than paired electrons? this seems to mean that they are less stable

The signature of pairing in nuclei is that when you plot the binding energy as a function of N for fixed Z, or as a function of Z for fixed N, you get an odd-even staggering, like a sawtooth. There is no such odd-even staggering for electronic binding energies: http://en.wikipedia.org/wiki/File:IonizationEnergyAtomicWeight.PNG
 

Related to Why is there no odd-even staggering for electronic binding energies?

1. What is the definition of "stability of the nucleus"?

The stability of the nucleus refers to the ability of a nucleus to maintain its structure and composition without undergoing spontaneous changes or decays.

2. How is the stability of the nucleus determined?

The stability of the nucleus is determined by the balance between the strong nuclear force, which holds the nucleus together, and the repulsive force between protons. If the number of protons and neutrons in a nucleus is within a certain range, the nucleus will be stable.

3. What factors affect the stability of the nucleus?

The number of protons and neutrons, the neutron-to-proton ratio, and the energy state of the nucleus are all factors that can affect the stability of a nucleus. Certain isotopes may also be more or less stable due to their specific nuclear structure.

4. Can the stability of a nucleus change over time?

Yes, the stability of a nucleus can change over time due to various factors such as radioactive decay, nuclear reactions, and changes in the environment. However, the stability of a nucleus is a fundamental property and does not change under normal circumstances.

5. Why is the stability of the nucleus important?

The stability of the nucleus is important because it determines the properties and behavior of atoms, which are the building blocks of all matter. Understanding the stability of the nucleus is crucial in fields such as nuclear physics, chemistry, and medicine.

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