- #1
Xyius
- 508
- 4
I am having a little trouble understanding this and I was wondering if I could get some help.
I understand that work done at constant volume is zero because since the volume isn't changing, there is no movement on the boundaries and therefore no work. But it isn't coming out mathematically. This is what I mean.
[tex]dU=\delta Q - \delta W[/tex]
[tex]dU=\delta Q - d(PV)[/tex]
[tex]dU=\delta Q - VdP-PdV[/tex]
[tex]dU=\delta Q - VdP[/tex]
Yet, my professor is saying that at constant volume, work is just...
[tex]dU=\delta Q[/tex]
This makes sense conceptually, but why isn't it making sense mathematically? How could I make VdP=0?
I understand that work done at constant volume is zero because since the volume isn't changing, there is no movement on the boundaries and therefore no work. But it isn't coming out mathematically. This is what I mean.
[tex]dU=\delta Q - \delta W[/tex]
[tex]dU=\delta Q - d(PV)[/tex]
[tex]dU=\delta Q - VdP-PdV[/tex]
[tex]dU=\delta Q - VdP[/tex]
Yet, my professor is saying that at constant volume, work is just...
[tex]dU=\delta Q[/tex]
This makes sense conceptually, but why isn't it making sense mathematically? How could I make VdP=0?