ajaysabarish said:the p orbital is involved in double bond
thank you for replying sir,but sir as far as i know,a pair of pi electrons get transferred to carbon orbitals the + and - charges form a bond.and it proceeds,iam asking how does the pi electron get transferred to carbon orbital,because the hybridized orbitals of carbon and pi orbital in which electrons are perpendicular.please replyBorek said:There are no double bonds in benzene.
Google "aromaticity".
Benzene is considered a resonance structure because it is not possible to accurately represent the molecule using a single Lewis structure. The actual structure of benzene is a combination of all possible resonance structures, resulting in a more stable molecule.
Resonance in benzene occurs due to the delocalization of electrons. The pi electrons in benzene are able to move freely throughout the ring, resulting in a more stable structure.
The delocalization of electrons in benzene leads to a more evenly distributed charge throughout the molecule, making it more stable. This also allows for the molecule to be less reactive compared to other unsaturated hydrocarbons.
If benzene did not exhibit resonance, it would have alternating single and double bonds, resulting in a less stable molecule. This would also make benzene more reactive and prone to addition reactions.
Other molecules that exhibit resonance include nitrobenzene, phenol, and other aromatic compounds. These molecules also have delocalized pi electrons, resulting in a more stable structure.