- #1
poul
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Homework Statement
Hey
I have a InAs wurtzite structure, and want to find the distance between the WZ [1 0 3/2] layers *surface coordinates*. I need it to find the angle of diffraction for the WZ [1 0 3/2] bragg peak, for a 15.32 keV beam. It is in fact a InAs nanowire, on a (111( Si substrate.
Homework Equations
The surface coordinates are given as, in cubic coordinates: a1=[1/2 0 -1/2]_c a2=[-1/2 1/2 0]_c a3=[1 1 1]_c
the reciprocal lattice of the surface coordinates, is:
b1=[2/3 2/3 -4/3]_c b2=[-2/3 4/3 -2/3]_c b3=[1/3 1/3 1/3]_c
The wurtzite structure is, in cubic coordinates:
a_1=[1/2 0 -1/2]_c a2=[-1/2 1/2 0]_c a3=[2/3 2/3 2/3]_c
and reciprocal lattice, for the Wurtzite structure is:
b_1 = [2/3 2/3 -4/3] b2= [-2/3 4/3 -2/3] b3=[1/2 1/2 1/2]_c
the length for the in-plane vectors are a=4.308 Å, and c=7.028 Å for out-of-plane.
Following basis vectors are described for such Wurtzite structure:
r_1=1/3a1 + 2/3a2, r2=2/3a1+1/3a2+1/2a3, r3=1/3a1 + 2/3a2 + 3/8a3, r4=2/3a1+1/3a2+7/8a3
The Attempt at a Solution
The distance between the layers, are given as 2pi/G_hkl. So it is basicly finding the length of the shortest reciprocal vector perpendicular to the plane.
From the above equations i know that the bragg peak [1 0 3/2]_surf, is the same as the bragg peak *7/6 7/6 -5/6]_c. and then i can calculate d as d=2pi/G_hkl = a_cubic/(sqrt(7/6^2+7/6^2+5/6^2)) = a_cubic/1.84
I know from geometry that a_cubic = sqrt(2)*a, so d=3.32 Å.
Is that right? And then i can just use 2*d*sin(theta)=lambda