X-rays: Distance between WZ [1 0 3/2]surf layers in InAs

  • Thread starter poul
  • Start date
  • Tags
    X-rays
In summary, the conversation discusses finding the distance between layers in an InAs wurtzite structure in order to calculate the angle of diffraction for a given beam energy. The distance can be calculated using the reciprocal lattice vectors and the final answer is determined to be 3.32 Å. It is suggested to provide more context and include units in the final answer. Overall, the approach taken by the individual seems correct.
  • #1
poul
17
0

Homework Statement



Hey

I have a InAs wurtzite structure, and want to find the distance between the WZ [1 0 3/2] layers *surface coordinates*. I need it to find the angle of diffraction for the WZ [1 0 3/2] bragg peak, for a 15.32 keV beam. It is in fact a InAs nanowire, on a (111( Si substrate.

Homework Equations


The surface coordinates are given as, in cubic coordinates: a1=[1/2 0 -1/2]_c a2=[-1/2 1/2 0]_c a3=[1 1 1]_c

the reciprocal lattice of the surface coordinates, is:
b1=[2/3 2/3 -4/3]_c b2=[-2/3 4/3 -2/3]_c b3=[1/3 1/3 1/3]_c

The wurtzite structure is, in cubic coordinates:
a_1=[1/2 0 -1/2]_c a2=[-1/2 1/2 0]_c a3=[2/3 2/3 2/3]_c

and reciprocal lattice, for the Wurtzite structure is:
b_1 = [2/3 2/3 -4/3] b2= [-2/3 4/3 -2/3] b3=[1/2 1/2 1/2]_c

the length for the in-plane vectors are a=4.308 Å, and c=7.028 Å for out-of-plane.

Following basis vectors are described for such Wurtzite structure:
r_1=1/3a1 + 2/3a2, r2=2/3a1+1/3a2+1/2a3, r3=1/3a1 + 2/3a2 + 3/8a3, r4=2/3a1+1/3a2+7/8a3

The Attempt at a Solution



The distance between the layers, are given as 2pi/G_hkl. So it is basicly finding the length of the shortest reciprocal vector perpendicular to the plane.

From the above equations i know that the bragg peak [1 0 3/2]_surf, is the same as the bragg peak *7/6 7/6 -5/6]_c. and then i can calculate d as d=2pi/G_hkl = a_cubic/(sqrt(7/6^2+7/6^2+5/6^2)) = a_cubic/1.84
I know from geometry that a_cubic = sqrt(2)*a, so d=3.32 Å.

Is that right? And then i can just use 2*d*sin(theta)=lambda
 
Physics news on Phys.org
  • #2
to find the angle of diffraction for the 15.32 keV beam.

Hello,

Yes, your approach is correct. The distance between layers can be calculated using the reciprocal lattice vectors as you have done. The final answer of 3.32 Å seems reasonable and can be used to find the angle of diffraction for the given beam energy. However, it would be helpful to provide more context and background information about the problem in order for others to understand and verify your solution. Additionally, it would be beneficial to include units in your final answer and show the calculations for finding the angle of diffraction. Overall, it seems like you have a good understanding of the problem and have approached it correctly. Keep up the good work!
 

1. What are X-rays?

X-rays are a type of electromagnetic radiation with a shorter wavelength than visible light. They were discovered in 1895 by German physicist Wilhelm Röntgen and have since been used in various fields, including medicine, industry, and scientific research.

2. How are X-rays produced?

X-rays are produced when high-speed electrons collide with a metal target, usually tungsten. This collision causes the electrons to slow down and release energy in the form of X-rays.

3. What are the applications of X-rays?

X-rays have many important applications, including medical imaging, security screening, and material analysis. They are also used in research to study the structure of materials, such as in the case of the distance between WZ [1 0 3/2]surf layers in InAs.

4. How do X-rays interact with matter?

X-rays can interact with matter in three ways: absorption, scattering, and fluorescence. In absorption, the X-rays pass through the material and are absorbed, which can be used for imaging purposes. In scattering, the X-rays are deflected in different directions, which can provide information about the structure of the material. In fluorescence, the atoms in the material absorb the X-rays and then re-emit them at a different energy level, which can also be used for imaging.

5. What safety precautions should be taken when working with X-rays?

X-rays can be harmful to human health if proper safety precautions are not taken. It is important to limit exposure to X-rays, wear protective gear, and follow proper procedures when handling X-ray equipment. Additionally, facilities that use X-rays must adhere to strict safety standards and regulations to ensure the safety of both workers and the general public.

Similar threads

  • Atomic and Condensed Matter
Replies
2
Views
3K
  • Precalculus Mathematics Homework Help
Replies
3
Views
886
  • Calculus
Replies
2
Views
1K
Replies
2
Views
1K
  • Math POTW for Secondary and High School Students
Replies
1
Views
2K
Replies
2
Views
1K
Replies
1
Views
1K
Replies
11
Views
60K
  • Calculus and Beyond Homework Help
Replies
1
Views
948
  • General Math
Replies
11
Views
3K
Back
Top