Recent content by 09jlk

Oh wow, so ∆t = (∆t')gamma -- you can just use the time dilation formula! So much easier than I was making it! Thank you -- I appreciate you leading me through it.

Event one -- she leaves and so it happens at zero. Event two, she arrives, and she's still with the origin if she's carrying it... so... are you saying that event two is happening again at zero? (I'm confused! I'm not sure if I am reading this correctly.)

Hm, that seems counterintuitive, since I am able to use the new distance (the one I was using before) and divide by the traveler's velocity in order to get ∆t' (at least, doing that got me the correct answer for part two.) -- but I still have to calculate ∆x' by saying ∆x' = γ(∆x - v∆t)...

Hmm, I'm not sure. This is where I'm getting most confused -- the stationary (earth) coordinate system versus her own moving coordinate system... So if she is carrying the coordinate system with her, then does that mean I should find a negative change in x? Why wouldn't I be able to use the...

So for x value -- I start at x=0 (traveler leaving Earth)...I know that if the traveler is going at 0.99c along this path of 26 light years, then her perceived length of path should be x' = x/γ = 26 ly * sqrt(1-(v/c)2). Converting to meters from light years and plugging in 0.99 for v/c, I got...

Homework Statement A space traveler takes off from Earth and moves at speed 0.99c toward star Vega, which is 26.00 ly distant. How much time will have elapsed by Earth clocks when the traveler reaches Vega? 2. The attempt at a solution I looked at the problem solution, which...

Ahh, pressing on the other side of the plug. Thank you!

Homework Statement The question states: The fresh water behind a reservoir dam has depth D=15 meters. A horizontal pipe 4.0cm in diameter passes through the dam at depth d=6.0m. A plug secures the pipe opening. (a) Find the magnitude of the frictional force between plug and pipe wall...