Recent content by 619313

1. I am studying for finals and I am trying to figure out how the author solved this dy/dx = 4*e^(0.8*x)-0.5y and y(0) =2 Rewrite into the form y = 4/1.3 *(e^(0.8x) - e^(-0.5x)) + 2e^(-0.5x) I solved by P(x) = 0.5y and Q(x) = 4*e^(0.8x) I have tried this numerous times and the...

For an analysis of a robot component: a Spur gear drive/train. How can I account for friction losses? I can calculate the torque, with neglecting friction. And what about the change in energy? I know power = torque*angular velocity

Thanks for the reply, I divided (2) by (1) but I have Tan(30) = (-B*sin(φ) + D)/ (B*cos(φ)) Am I missing something?

I have having trouble solving this statics problem, I sum up the forces and have C*cos(30) - B*cos(phi) = 0 in the positive x direction and C*sin(30) + B*sin(phi) - D =0 in the positive y direction B = 275 lbs and D = 300lbs I need to solve for C and phi, I have tried substitution...

first, thanks so much for the help just to make sure I fully understand all of these triple integrals, to set it up in spherical I should get 0<= theta<= 2pi, 0<= phi <= pi, 0<= p <= R, where the integrand is (p^4) (sin(FI))^3 dp dphI dtheta

Fantastic! Yea I know that it goes dz dy dx now How about if I rewrite to cylindrical coordinates? 0<= theta <= 2pi , 0<=r<=R , -sqrt(R^2-r^2)<=z<= sqrt(R^2-r^2) with the integrand being r^3 dz dr dtheta

[b]1. consider the triple integral (x^2 +Y^2) dV where it is bounded by a solid sphere of radius R. Set up the integral using rectangular coordinatesI tried setting this up with the bounds [ -sqrt(R^2-x^2-Y^2) <= Z <= sqrt(R^2-x^2-Y^2) , -R <= X <= R , -sqrt(R^2-x^2) <= Y <= sqrt(R^2-x^2) ]...