Recent content by 7C0A0A5

I have no idea how to do this :'( really the only part I don't understand is the ending part...like for the infinite sum of (1/n(n+1))....I know you start of by partial fractions...then you just plug in a few numbers for n. so I end up with: (1 - 1/2) + (1/2 - 1/3) + (1/3 - 1/4) + ...

K thanks That thread did help and I got the right answer...don't fully understand why but I'll ask my proffesor during his office hours. Thanks a bunch guys.

Well...it doesn't give me the velocity of the bullet and that is what I'm trying to find...so when I solved for the velocity I got 218 m/s. But that is the velocity perpendicular to the plane, right? so then I divided that number by the cos of 30 and got 252 which is also wrong.

A uniform thin rod of length 0.40 m and mass 3.5 kg can rotate in a horizontal plane about a vertical axis through its center. The rod is at rest when a 3.0-g bullet traveling in the horizontal plane of the rod is fired into one end of the rod. As viewed from above, the direction of the bullet's...

In the image {08_53.gif}, a block is moved down an incline a distance of 5.0 m from point A to point B by a force F that is parallel to the incline and has a magnitude of 2.3 N. The magnitude of the frictional force acting on the block is 10 N. If the kinetic energy of the block increases by 35...

#2) Correct K=\frac{1}{2} mv^2 (a) K=\frac{1}{2} (6kg)(2\frac{m}{s})^2=12J (b) K=\frac{1}{2} (4kg)(3\frac{m}{s})^2=18J (c) K=\frac{1}{2} (2kg)(5\frac{m}{s})^2=25J (d) K=\frac{1}{2} (6kg)(2\frac{m}{s})^2=27J Therefore...(d) is the correct answer [if I did it correctly :cool: ] #3)...

Thanks Parth Dave I just finished problem 7 and got all the right answers...I do appreciate your input...now on to the next problems :cool: and I understand it (which is always a plus)

Finally the graph... I don't know how to add pictures...so I'll explain the graph __________ | | | | | | | |----------- 4 |\| | | | | | |----------- 0 | |\|_|_|_|_| |----------- -4 | | | | | | | 0 1 2 3 4 5 ok, ok it is a crude graph...now the explanation of...

Springs, Vectors, and a graph Part 2 Now the Vector problem... 7. [HRW6 7.PN.20.] A force F = (2.9 i + 7.5 j + 8.0 k) N acts on a 2.00 kg object that moves from an initial position of di = (3.0 i - 2.0 j + 5.0 k) m to a final position of df = (-5.0 i + 3.9 j + 7.1 k) m in 4.3 s (a) Find...

This is my first post...and I hope I am doing this correctly...I know this isn't a place to "get my homework done for me". I just want to know how to do it. 3. [HRW6 7.P.022.] A 220 g block is dropped onto a relaxed vertical spring that has a spring constant of k = 2.8 N/cm. The block...