Sorry. The whole question was:
If the heat of combustion of propanol is -1843.7 kJ/mol, what is the heat of formation of propanol? Write the equation for the heat of formation for propanol and include the energy as a term in the equation.
I got the heat of formation to be -304 kJ. I'm not...
I stumbled upon another way to solve this question without using the derivative method since according to my teacher, the derivative method is supposely too advanced for our level. Anyways, putting in a 1 in the bottom so it becomes:
\frac {\sqrt[3]{1+x^2} - 1}{(1+x^2)-1}
and then taking a...
So by using this method, taking a difference of cubes on the bottom, the limit as t approaches 1 is \frac {1}{3} which is the same answer as by using L'Hospital's Rule such as that in post #2. I'm sorry in advance for my stupidity but the bottom (which was originally x^2 ) how did it become...
So working backwards I got {\sqrt[3] {x} } . Using the formula, replacing x with a 1+h then: \frac {\sqrt[3] {1+h} - \sqrt[3] 1} {h} which is \lim_{h\rightarrow 0}\frac {\sqrt[3]{1+h} -1}{h} . Going back to \lim_{h\rightarrow 0}{\sqrt[3] {x} } and replacing x with 0 gives you 0. I don't...
I thought I got it but I didn't. \lim_{h\rightarrow 0}\frac {\sqrt[3]{1+h} -1}{h} looks like is from the formula \lim_{h\rightarrow 0}\frac{f(a+h)-f(a)}{h} . Or perhaps not? Could anyone give me another hint or suggestion involving the question using the method above,replacing x^2 with h...
If you have a repeating decimal such as 0.45454545... and the question was asking for it to be expressed as an infinite series and find the sum of the series, would it be correct to approach it like this:
0.45454545... = \frac {45}{100}+ \frac{45}{10000} + \frac{45}{1000000}...
so...
1) \lim_{x\rightarrow 0}\frac {\sqrt[3]{1+x^2} -1}{x^2}
I tried doing a difference of cubes to the top and I got: \frac{\sqrt[3]{1+x^2}-1 ((\sqrt[3]{1+x^2})^2 + \sqrt[3]{1+x^2} + 1)} {x^2}
I know you need to get rid of the x^2 on the bottom of the equation but now I'm stuck. Am I...
Hmmm...alright.It actually somewhat makes sense. There is only an x-component to the electrostatic force so starting with what nylex suggested Fe=Ftsinø,would it be true then to say that:
Fe=Ft-Fgsinø
= ma- mgsinø
My rationale for this is that Earth exerts a downward force F=-mg on...
Well,I've tried attempting this problem but I am not sure if I approached it the right way. Here is a link for the diagram and the question.
[PLAIN]http://img.photobucket.com/albums/v367/crazy_cat_lady/physics/diagram1.bmp[/URL]
If anyone could check it over and point out any mistakes...