Recent content by aatgomez

Right I realize that, that's what I don't know how to find.

I see that there's potential energy before the arrow is shot. That's where the .2 m come in. But I still don't know how to solve it. A little more help please?

Ok, so if I find the initial velocity and the final velocity as if I were doing projectile problem then I can find W=1/2mvf^2 - 1/2mvi^2 then I could set W equal to 1/2kd^2 final - 1/2kd^2 initial and find k. Is that correct?

oh yes, sorry W=1/2kd^2 final - 1/2kd^2 initial It would have to be 0 initially and I'm thinking 45 degrees?

In preparing to shoot an arrow, an archer pulls a bowstring back 20 cm=.2 m. The arrow can reach a horizontal distance of 300 m and the arrow weighs 200 g. Find k. m=.2 kg W=1/2kd final- 1/2kd initial Fs=-kx Not really sure where to begin, and I've been trying for a while now. :confused:

1. Homework Statement An object consists of 3 connected masses as seen in the figure. None of the surfaces have friction except the surface on m1 which has the coefficients μs=0.4 y μk=0.3. What is the acceleration of each one of the masses? It looks like the following image but m1 is the...

Homework Statement An object consists of 3 connected masses as seen in the figure. None of the surfaces have friction except the surface on m1 which has the coefficients μs=0.4 y μk=0.3. What is the acceleration of each one of the masses? It looks like the following image but m1 is the table...