Recent content by abhip

After you apply L Hospital for the first time u get 5^nln(5)/1 now write that expression as ln5/5^-n...this is a form of k/0 where k is a constant...this form will tend to infinity if k is positive else minus infinity

Oh thank you i got it now using polar coordinates...thank you very much...love this forum..it's good that you people are able to solve our doubts it's just impossible getting doubts cleared back at my place as the teachers themselves submit on seeing such doubts...and what i like most is u...

1... but what about b^2 +c^2 how do i introduce them into the inequality because i have a trigonometric expression on the RHS

but how and what to replace the trigonometric expression on RHS of the inequality with as for LHS it can be written as 3(x+1)^2 +1

3x^2+6x+4>=csinx-bcosx x belongs to real numbers not how to get a relation with b^2 and C^2 sorry I am finding it difficult using the exponent feature

i had tried tat approach of finding df(x)/dx>=0 but can't relate to what has to be found in the question.

The function is one-one find the value of b^2+c^2[f(x)=x^3+3x^2+4x+bsinx+ccosxI tried the approach of monotonocity as a one one function will be strictly inc or decreasing in it's domain but I'm not being able to figure out b^2+c^2

Thank you very much for the approach it was helpful but after setting g(x)=f(x)+f(x+4) and knowing the fact g(x) has a period 2 how to relate if to f(x).Is there any approach to do so or do i have to opt for trial and error.

f(x)+f(x+4)=f(x+2)+f(x+6) where all functions are real valued