Here's 2 more I am having difficulty with, I'll show you what I came up with or what I think the answer is
1. 2x = 3y^2
(sqrt 2x/3) = 3y/3
y = sqrt (2x/3)
Symmetric to the X-axis
2. x^2 + 4y^2=16
not symmetric to any axis
Thanks for the help, although I am a bit confused. These numbers you came up with are the numbers for which the domain cannot be, correct? Is that the final answer I should be coming up with?
I have these three inequalities that I am supposed to solve, I think I came up with the right answer but I'm not even 100% sure it's in the correct format.
A. 6x^2 < 6+5x
my work:
6x^2-5x-6 < 0
solutions are then 3/2 and -2/3
so the answer I got is:
-2/3 < x < 3/2
B. x^2+8x > 0
my...
I have a lot of questions and I know I'm supposed to show all my work but the post would be insanely long, so I will show you what answers I have come up with on the ones that I managed to get that far. I know how to do these but I often get hung up on the fractions and trying to get rid of the...