excessive recoil due to it being light, which is what i stated in my huge paragraph! :P so ye "that IS what US guys have been trying to get at all this time"!
maybe you can assume that at the point where the 1st block contacts the spring of the 2nd block, the velocity of the 1st block is still 8 m/s... Then you can just look focus on the time frame in which the whole spring compression occurs, knowing that the initial velocity of the 1st block when it...
after defining your variables see if you are famliar with the impulse momentum formula:
mvf - mvi = momentum (where vf = final velocity and vi = initial velocity)
impluse = Force*delta t
impulse = momentum... maybe you can go about solving from there
no... why are u trying to solve for impulse when you have to determine force? what are your known and unknown variables? define them... Delta t = 0.012s, massball = ... and so on
hmm ok i seem to be getting the concept... let me see if i can state mathematically what hage567 mentioned..
2 resistors in parallel:
--> 1/R = 1/R1 + 1/R2 where 1 and 2 denote the resistors
--> I/V = I/V + I/V (same way of writing above eqn)
so if resistor 1 is very large and...
ahh excellent so i seem to understand from what you said that the current "favors" the path with the lower resistance. But the thing is when you place an ammeter in series, all the current runs through it anyways (and it should if you want an accurate reading). Why would making it in parallel...
The 1st step, you should do is draw a free body diagram for the hanging sign, that shows the forces acting on it. Include in your free body diagram, the angles of the rope.
2nd step should be listing the relevant Force equations in the x and y direction.
Hint: (Fnet)x = 0 = ...
for every action there's an equal and opposite reaction :Newton's 3rd law
Therefore ,I am guessing ejecting a mass (mass 1) from another mass (mass 2 which is your platform), would make mass 2 move backwards...
But from Newton's 2nd law we know F=ma... and mass is inversely proportional to...
umm sorry i still don't understand the answer to 3. Why would all the current run through the ammeter and reach a finite value. What do you mean by that? Isn't the current divided because the ammeter is in parallel (ie total current = current(resistor) + current(ammeter)) . For problem#4, my...
Homework Statement
Hey, How is everyone? I am working on a lab dealing with DC circuits. I am a bit confused about voltmeters and ammeters. We used a carbon composition resistor which obeys Ohm's law and therefore is a linear device. My Paint drawing aren't too pretty but I hope they convey...