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Homework Statement is there no square root for a negative number? is there no solution for this? q=-1 r=2 the square root of 2q - 5r The Attempt at a Solution 2x-1 - 5x2 = -12 sqaure root of -12? my calculator doesn't come up with a answer for the square root.

thankyou heaps guys for your help..

so how do i plug this into a formula for KE? the only formula i have for KE is 1/2M*Vsquared.. how do i work out the velocity of the trolley at DE? the difference in PE from AB to DE is 78.4 joules

im sorry i don't really understand.. the PE of DE is relative to C as that is the 274.4 joules is what i thought. sorry i missed some of the question "b) if the potential energy of the trolley AT LOCATION DE is 274.4 Joules, determine its kinetic energy as it moves along DE?" is the question...

thankyou.. with b) is it that the KE must be the same as the PE?

Homework Statement **please check diagram i have attached**i have a few problems all relevant to this information a trolley with mass of 4kg moves without friction. initially the trolley is on AB and moving to the right with a velocity of 10ms. DE is 2m above AB and C is 5m below C a) what...

the answer i am getting is 1080m

Homework Statement a rail carraige has a mass of 1200kg. the train engine shunts it along the track giving it an average accleration of 0.6ms-2. determine the distance traveled by the carraige in 60 seconds if started from rest. Homework Equations i think its something like V*T +...

props to you.

thankyou but this is to work out the distance yeah? v0=constant velocity? time taken to stop would be 18/5? so t = 3.6 so (18*3.6) + (5/2*3.6^2) ?

sorry i don't mean 5mssquared i ment 5 ms per s

then the distance of deeceration is constant speed / 5mssquared?

is it constant speed times time? if i do this tho my equation is 18 X .52 yes? 9.36 metres?

is it something like cos65 X 100

of the accelaration of the box down the ramp.