Okay so...
emf= -N A cos 0 (change in B/change in t)
=-139 turns*(0.01035 m^2)*1*(0.952 T/S)
=-1.3696 V
I=E/R
=-1.3696 V/ 0.502 ohm
=-2.728
B=N*(4pi*10^-7)*I/2R
-this is the equation for the magnitude of the magnetic field at the center of a flat circular loop consisting of N turns, each of...
So I did I=E/R to calculate current, then used B=(4pi*10^-7)*I/2*pi*r to get magnetic field but still it's different from the answer. :( I'm just stuck.
Homework Statement
A flat circular coil with 139 turns, a radius of 5.74 x 10-2 m, and a resistance of 0.502 Ω is exposed to an external magnetic field that is directed perpendicular to the plane of the coil. The magnitude of the external magnetic field is changing at a rate of ΔB/Δt =...
Homework Statement
Assume a liquid is flowing through a pipe of cross-sectional area A at pressure P and velocity v. If, at some point, the area decreases, then;
-velocity increase, pressure remains same
-velocity increases, pressure decreases
-velocity increases, pressure increases
correct...