Homework Statement What is
T=2pi[(sqrt)l/g] rearranged for l= ?
Homework Equations
The Attempt at a Solution
Ive tried a few but I just don't know how to do this with sqrt's of a fraction involved.
Ok so the intially stored Ep is Fx and which makes the Ek the same as Ep when the pellet is fired. So to find the velocity would I take the 1/2 out of the 1/2mv^2 equation? Or would it remain the same?
Thanks for your help Cepheid, I am taking physics through correspondance and It becomes very painful when I miss something from the content and you have eased the pain!
Would it be hookes law, rearranged to give me the spring constant?
How would I use that to find the initial energy stored in the spring?
I think I could use some clarification on how the energy of a spring works. My understanding is that force being applied to the spring is being stored as...
Ohhh ok, thanks for the clarification on the conservation, though the title is pretty self explanatory lol . I was interpreting Ep=-Ek in the wrong sense. So, I can find the ep at any point in the circle by mg(hcos theta), find the Ek by subtracting Ep from Me and then Solve for Velocity...
So find the Potential Energy by mghcos(theta) and the Kinetic energy will be equal and opposite to it? Then derive the Kenetic energy equation to find velocity?
Homework Statement A 0.160 kg ball attached to a light cord is swung in a vertical circle of radius 70.0 cm. At the top of the swing, the speed of the ball is 3.26 m/s. The centre of the circle is 1.50 m above the floor. What is the velocity if the ball is 30 degrees below the horizontal...
Homework Statement
A toy company hires you to construct a device that uses a small spring to launch 15 g foam pellets. The spring requires an average force of 5.70 N to compress it 1.30 cm. Determine the speed of one of the foam pellets as it leaves the spring.
Homework Equations...
Homework Statement A firewoman opens the fire hose, and water sprays forward. What is the action force and reaction force?
Homework Equationsnone
The Attempt at a Solution
I was thinking that the action force would be water pushing on air and reaction air pushing on water? But how...
So this is what I got and I am confident that it is correct, however I am unsure about the negative. Would the force that I calculated from player 1 be in the same direction as the acceleration
?(away from the collision) Making the Force applied to player 2 positive?
F=ma
Fp1=55(-15.6)...