Rearranging period of pendulum equation to find length

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Homework Help Overview

The discussion revolves around rearranging the equation for the period of a pendulum, T = 2π√(l/g), to solve for the length, l. Participants are exploring the manipulation of this equation, particularly focusing on the challenges posed by the square root and fraction involved.

Discussion Character

  • Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the method of squaring both sides to eliminate the square root. There is uncertainty about the correctness of the resulting expression for l and whether all factors have been appropriately squared.

Discussion Status

The conversation is ongoing, with some participants providing suggestions on how to approach the problem. There is a recognition of potential errors in the manipulation of the equation, particularly regarding the treatment of the 2π factor.

Contextual Notes

Participants are working under the constraints of homework guidelines, which may limit the types of assistance they can provide to one another. There is an emphasis on understanding the algebraic manipulation rather than simply arriving at the correct answer.

Adam17
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Homework Statement

What is
T=2pi[(sqrt)l/g] rearranged for l= ?



Homework Equations





The Attempt at a Solution


Ive tried a few but I just don't know how to do this with sqrt's of a fraction involved.
 
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Eliminate the square root by squaring both sides.
 
Ok,so what I end up with after that is l=T^2g/2pi. Which is wrong as its not giving me the correct answer.
 
When you square both sides, don't forget that you also have to square the factor of 2[itex]\pi[/itex]
 

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