Recent content by adeelrizvi

I really appreciate your help. I hope we are correct but it will be good to know if someone else here can verify our solution.

Solution: dW= F.dr dW= {(m*v^2)/r}dr (v=k/mr) dW= {(k^2/m)*(1*r^3)}dr Integrate this with limits Ro to R W = [(k^2)/(2m)]*[(1/Ro^2) - (1/R^2)] <----Answer Please check and let me know if this seems correct to you? Thanks

I guess you are right. I was taking the wrong assumption. If angular momentum is conserved then velocity increases if radius decreases. Now when you have corrected me I think my solution to the problem was not correct either. Can you please verify that for me as well? Thanks

You think my solution is correct? Can someone else also please confirm this. v=rw, w is constant. r decreases so v decreases as well. Correct me if I am wrong. Angular momentum I believe is conserved.

Q) A particle of mass 'm' attached to a string rotates with velocity Vo when the length of the string is Ro. How much work is done in shortening the string to R? One way I thought about doing this was: W= {(m*r*w^2) * r}dr and integrate this from R to Ro But I am not sure if that is...