Recent content by ADGigus

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    Graduate 2nd order with exponential and constant on right side

    it's ok Yes I'm sure it's correct, it's coming from the expression of a Schottky diode (current density vs Voltage) so it's : J = a(Exp(-bV) -1) because you want 0 current at bias of 0 Volts... I already try many way to solve this equations, til now I'm fully stuck Even numerically I...
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    Graduate 2nd order with exponential and constant on right side

    ok but my problem is in the followings... Thank you for your very quick answer and the welcome. Yes I agree til there it's easy but it's the following that gives me troubles. so starting from : y'' = a Exp(-b y) -a y ' y'' = y ' a Exp(-b y) -a y ' after the integration on y on both...
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    Graduate 2nd order with exponential and constant on right side

    Hi everybody, How do I solve this differential equation ??: y'' = a(Exp(-b*y)-1) ; where a, b are constants with the boundaries conditions : y'(x=0)=-K1 y'(x=L)=0 without the constant term I can do y''*y' = y' a Exp(-b y) then integrate it \ {1/2} (y')^2= {a/b}...