Recent content by adl2114

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    Webpage title: What are the Rate Equations for a Parallel Reversible Reaction?

    I know the rate equations for a parallel reaction are d[A]/dt =-k1[A]-k2[A] d[B]/dt =k1[A] d[C]/dt =k2[A] and I know that the rate equations for a reversible reaction are d[A1]/dt =-k1[A1]+k2[A2] d[A2]/dt =k1[A1]-k2[A2]-k3[A2]+k4[A3] d[A3]/dt =k3[A2]-k4[A3] But what would d[A]/dt...
    • adl2114
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    • Rate Reaction Reaction rate
    • Replies: 1
    • Forum: Chemistry
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    Finding the period of a differential equation?

    find the period of the solution to this differential equation: 2y'' + 4y' + y = 0 I used the complementary equation 2r^2 + 4r + 1 = 0 and then used the quadratic equation to factor that into 2 roots of -2 + 2^(1/2) and -2 - 2^(1/2) and I know that 2 real, distinct roots means there is no...
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    Solving First Order Diff EQ: Salt Tank Example

    perfect! I know I did check it myself but I am very poor in math skills I like to have another set of eyes thanks so much for your quick responses
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    Solving First Order Diff EQ: Salt Tank Example

    Ok if what I have so far is correct solving for y gets me: y(t)=20 + e^(-2t/5)C then assuming the inital condition of y(0)=0 I get C= -20 so the final answer would be y(t)=20-20e^(-2t/5) can someone verify this is correct?
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    Solving First Order Diff EQ: Salt Tank Example

    ok so here's what i got so far: dy/dt=8-(4y/10) dy/dt=(80-4y)/10 dy/(80-4y)=dt/10 integrate to get (-1/4)ln(80-4y)=t/10 + C what do you think?
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    Solving First Order Diff EQ: Salt Tank Example

    Homework Statement Salt water pours into a 10 liter tank at a rate of 4 l/min. Its concentration is 2 g/l. The brine in the tank is well mixed and it drains out at a rate of 4 l/min. Call y the grams of salt in the tank at time t. The tank is initially full of fresh water. Solve the...