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Homework Help: Finding the period of a differential equation?

  1. Aug 11, 2010 #1
    find the period of the solution to this differential equation:

    2y'' + 4y' + y = 0

    I used the complementary equation 2r^2 + 4r + 1 = 0 and then used the quadratic equation to factor that into 2 roots of -2 + 2^(1/2) and -2 - 2^(1/2) and I know that 2 real, distinct roots means there is no period but If the problem had been different how would I go about finding the period after determining the roots?
  2. jcsd
  3. Aug 11, 2010 #2

    Char. Limit

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    Gold Member

    Well, first, your roots are off by a scaling factor of 1/2. And assuming that both roots are imaginary, well, e^(ix) is periodic, but I'm not sure of the period...
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