find the period of the solution to this differential equation:(adsbygoogle = window.adsbygoogle || []).push({});

2y'' + 4y' + y = 0

I used the complementary equation 2r^2 + 4r + 1 = 0 and then used the quadratic equation to factor that into 2 roots of -2 + 2^(1/2) and -2 - 2^(1/2) and I know that 2 real, distinct roots means there is no period but If the problem had been different how would I go about finding the period after determining the roots?

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# Homework Help: Finding the period of a differential equation?

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