Recent content by admajoremdeigloriam

how long did the light take to travel the glass? thats when the thickness counts you can get your index once you figure this out as the light goes through the glass, the frequency doesn't change just the wavelength what does this tell you?

but we are not iven the E of the particle?

the stopping potential hits 0 at threshold frequency of 43.9 e13 Hz

we are given a graph of stopping potential (y-axis) vs frequency (x-axis) that's it

ive used E=hf hf= Kmax + PHI Kmax=eV all it does is bring me round and round

if you are given the stopping potential and the threshold frequency, how do you calculate Planck's constant from it?

your rays on your drawing is wrong too. You should try drawing it to scale, so you know for sure that the location of the images are correct. In optics, don't just sketch the diagrams cause the drawings help you with your calculations.

I have a simple question that I can't seem to answer... why is it that when an object is at the focal point of a converging lense, the image is at infinity? How can you show this through ray diagrams?

the ray diagram should have given you a clue to the image's location, magnification, and orientation. it is actually pretty easy.

don't get me wrong, i do appreciate (a lot) the help. it just amazes me how simple the problem is, but it took me so long to figure it out

oh sorry its 750/900

how did u type in the lambda sign? so i don't have to type it all the time next time lol

thanks for the help, but i actually got it already from my original equation which i got n2/n1 = lambda1/lambda2 I actually factored (700nm/900nm) smaller and got n2=n1 5/6 which gives me n1=6 and n2=5 which is the same as what you got :)

do u mean trial and error? i don't know if this is correct, but if i use n<=(less than or equal)d/lambda there's going to be too many maximas on both wavelengths (thousands of them)

still no takers?