Recent content by adventq

okay...when I assumed a1 not equal to a2 which i wasnt doing originally, i got 2T-m_2*g=-m_2*a_2 and T=m_1*a_1 sbsitiuting and shifting things around I got: a_1=(m_2*g-m_2*a_2)/(2*m_1) does thi seem right? should my anyswer depend on a_2 or are they assumed to be the same, therefor...

how does a=(m_2*g)/(2*m_1+m_2) sound?

any smart person have any clue about where i went wrong?

Any thoughts?

here is the image

Thanks for the help.

sorry...forgot it at first

So the problem I am working on is: In the figure, find an expression for the acceleration of (assume that the table is frictionless). I have attached the figure of reference. I have so far tried to solve by first looking at m2 to get: 2T-m_2*g=m_2*a so T= (m_2*(a+g))/2...

I did F=mu_s*4*g-mu_k*7*g and got F=9.8 did 9.8=m*a=7*a a=1.4 plugged that into 5=(1/2)*1.4*t^2 and t=2.67 sec

is t=2.67 sec right?

So for the top F=mu_s*m_top*g and for the bottom F=(-mu_s*(m_top+m_bot)*g)-(mu_k*(m_top+m_bot)*g)? I am still pretty confused about the equations I am supposed to use. Physics is pretty much my worst subject so I am pretty clueless most of the time.

So the max force would be f_s=mu_s*N. So do you use the N of the whol system so N=(m_top+m_bot)*g or just the top block N=m_top*g? So when we get the F we just set it equal to F=ma and solve for a? Do I use the combined masses for m? Was I right originally in saying that I plug the a into...

Well I keep trying to go about it by solving for acceleration but that isn't getting me anywhere. So what I have is: Top: F_x=m_top*a+mu_s*m_top*g Bottom: F_x=-mu_s*(m_top+m_bot)*g then do I set them equal and solve for a? Then I have been trying to plug a into the eqn...

Thanks for the help with number 2 radou. Anyone have any advice for number 3?

Any suggestions? Could certainly use some help from those out there much smarter in this subject than I :cry: