Recent content by agentsanta

Alright I tried what you suggested ...I have no idea what that is x.X I know how to do integration and stuff but I've never integrated dt or dP before Any tips? Or am I biting off more than I can chew and should simplify my model?

Hey I'll try to digest what you said Thanks for the reply though I've only done enough calculus to barely understand what's going on I haven't done integration by parts but I use wolframalpha for that XD Thanks

Hey, I am doing a project on population growth modelling, and I have hit a brick wall in trying to derive a function to represent an aspect of my population I understand that the derivative of a logistic function is P'(t)=P(t)(1-P(t)) and from there one can obtain the function P(t)=...

Sorry for the late reply I was a little busy Thx for all the replies, I get it now

Ok, so I sort of have an idea of what kinetic energy is but I'm still kind of confused. I'm confused mainly because of the equation. Every source I've gone to has just given me the equation EK=1/2mv^2 but none of the sources mentions where it came from or what it means It almost seems like...

So, tractor applies 100n to ground ground applies 100n to tractor tractor applies Xn to load load applies Xn to tractor in opposite direction X doesn't equal 100n Is the above correct? Sorry >.> I'm not very good at this stuff and I don't have a teacher What would affect the strength of X?

errrr I'm not really sure to be honest I'm assuming the tractor is applying force to the ground So if the tractor exerts 100n onto the ground and the ground pushes the tractor 100n forward? Then the tractor exerts force on the load right? But wouldn't the load pull back with the exact same force...

Homework Statement A tractor is pulling a heavy weight behind it by a rope. If, according to Newton's third law, the load is pulling back as hard as the tractor is pulling forward, then why does the tractor move? Something else I don't really get: A fishline will break when a force of more...

OK, I think I know what you are saying. The ball's velocity is 0 at its maximum height, where it cannot get any higher. So I tried the full equation d=VOt +(at^2)/2 d=VO(2s) + ((-9.8m/s^2) * (2s)^2)/2 d=VO(2s) + ((-9.8m/s^2) * 2s^2) d=VO(2s) + (-19.6m) at= Vf-VO -9.8m/s^2 * 2s= 0-VO...

Homework Statement A ball is thrown from the ground to the top of the school flagpole. If it returns to the ground after 4.0 sec, what is the height of the flagpole in meters? g=9.8m/s^2 Homework Equations Not really sure. Tried d= (at^2)/2 Didn't really work out though... The Attempt...