Ehi men, do you know how much it costs to put something in orbit?
Actually it is about 10000 to 50000 Eur for each Kg you want to take up.
And you leave it in a LEO (Low Earth Orbit) or in the best case ine a GTO (an elliptic orbit with perigeum LEO orbit and apogeum GEOstationary...
if everything is in parallel, no matter what you put, the voltage in the parallel is given by the voltage of the dc battery so the current in the resistor is V/R.
In real word however, each battery has an internal resistor in series and a current generator has a resistor in parallel, so you...
Well, nobody here talked enough about Nuclear Electric Propulsion (NEP).
Nuclear Termal Rockets (NTR) are a very good possibility to low down the costs to go from ground to space, but are at all not good for interplanetary missions.
I explain:
Chemical propulsion can have a maximum specific...
is there no friction?
in this case the interaction force between the block and the wedge is the normal vincular reaction, that is equal to the normal compnent of the block weight that is:
N=mg\cos\alpha
where alpha is the lower angle of the wedge. So the horizontal force between the wedge and...
Then, to find the speed upon emerging you must substitute the sand length [15 m] in the x formula, and find the time you need to emerge from the sand. When you find this you substitute this t in the speed formula (\dot{x}) and find the emerging speed.
And you hav finished all the problems.
Second: you must use the Newton´s law. Acceleration equals force so that if x is space then speed and acceleration are \dot{x} and \ddot{x} where the dots mean derivation in time. If \mu is the friction coefficient the Newton´s law gives
m\ddot{x}=-\mu mg\rightarrow\ddot{x}=-\mu g
where g=9,81...
First: if you use breaks then you have that the maximum static force is given by
\mu N\cos\vartheta
and the parallel to street component of the car weight N is
N sen\vartheta
You start to move when the second is bigger than the first, so the maximum angle is given by
Nsen\vartheta=\mu...
You should find the launch angle with the arctan of h/(x/2). If you have no air drag the landing angle is the same. So, if you find the angle you can find the x and y velocities when the ball lands. If there is no friction the x velocity remains the same. To find y velocity you must know if the...
you must write the dynamic equation of the ball on the spheroid dividing normal and parallel forces to the surface. When the centrifugal acceleration equals the normal force to the surface made by the normal component of the weight of the ball then the small object leaves the spheroid