Recent content by airking95

Can you please show me, how you would solve this please ??

How do I solve it without putting Vf as 0, and yes the vertical height difference is 5.9m below the launching point.

First I just used Pythagorean therm to find Δd. 482+5.92= c2 c= 48.36 Used equation to find time Δd = VfΔt-0.5(a)Δt2 48.36= -0.5(-9.8)Δt2 48.36 = 4.9Δt2 48.36/4.9=Δt2 9.86 =Δt2 + - 3.14 = Δt s=d/t s=48.36/3.14 s=15.4 m/s I think I was suppose to do something with 15 degrees.

Homework Statement A daredevil motorcyclist attempts to leap a 48m wide gorge. At the side where the cyclist starts, the ground slopes upward at an angle of 15 degrees. Beyond the far rim, the ground is level and is 5.9m below the near rim. what is the minimum speed necessary for the cyclist to...