Recent content by AJDangles

Ok... v = d/dt (sin (wt + θ)) v = cos (wt + θ) * d/dt (wt + θ) via chain rule. v = (w * d/dt (t) * d/dt (θ)) * cos (wt + θ) v = (1w + 0) * cos (wt + θ) v = w cos (wt + θ) ? Sorry if my math is rusty; so cosw is different than w cos? Is cosw assumed to be cos (w)?

cos (w) (wt + θ) ?

For the pressure, would the last equation i have to use to derive be p (t) = (mv)/(t * area)?

and then a = d (cos (w) (wt + θ)) / dt a = cos (w) (w + 0) a = w cos (w)

Wooooow it's all coming back. That rush of knowledge. Ok thanks. I think it got it? = cos (wt + θ) * d (wt+θ)/dt = cos (wt + θ) * w = cosw (wt + θ) v = cos(w)^2 (t) + cos(w)θ

I'm really rusty on my calculus so this could be ugly but here goes... dv = d (sin(wt + θ)) / dt dv * dt = d (sinwt + sinθ) dv * dt = d*sin*wt + d sinθ dv = (d*sin*wt + dsinθ) / dt dv = sinw + dsinθ do i have to integrate or use a trig identity here?

would the first answer therefore be, v = (sin (wt +θ)) / ΔT? edit: i mean, v = (sin (wt +θ)) / dt? because we're talking the instan velocity therefore derivative and the slope of the tangent

v = delta X / delta T

v = d/t Simple enough or are you looking for something else?

Homework Statement For each expression of displacement (x) below, write down the mathematical functions for velocity (v), acceleration (a), and pressure (Pa). Assume a maximum amplitude (A) of displacement = 1. Units are not required. Hint: Think about the phase relationships of pendular...

Wow, fail. K here it is last time lol:

Sorry. Here is the diagram and work:

Diagram and work:

Homework Statement A thin charged rod of length L lies along the x-axis as shown in the diagram below. The charge on the rod is distributed with a density of λ= c x (C /m) where c is a constant. What is the potential at a point (0,y)? (Your answer should be in terms k, c, L, and y). See...

Take the force of gravity times a component of the angle, multiply by the charge of a proton?