Recent content by alaa_137

yeah, and its jordan form is just as the original matrix. I tried another rank 1 matrix to see if i come across a rule for jordan forms for rank 1 matrices... but i didn't find anything special...

t1=1 , t2=0

if rank = 1 then all eigenvalues are zero, right ?

alright so everything i said is wrong i guess. i just tried to get to SOMEthing... because i came to a dead end... and yes i know about Jordan forms... How can I use that for the proof?

Hey guys I hope I'm in the right place... I have this question I've been trying to solve for too long: Let A be an nxn matrix, rankA=1 , and n>1 . Prove that A is either nilpotent or diagonalizable. My best attempt was: if A is not diagonalizable then det(A)=0 then there is a k>0 such that A^k...