Recent content by alancj

There's still a missing proton. Uranium is 92, hydrogen is 1... that's 93 but Pu is 94. So like the others that I've tried one part matches (U-235 and D add to 237) but the other doesn't. Should I just invent some isotopes then? I guess the graders would have to have a list of possible...

Sure, I could just invent some isotopes and call it good but I wanted to find some real isotopes that commonly result from a Pu-239 fission event. If I used the products from a U-235 fission equation they wouldn't add up, since I'm supposed to solve it for Pu-239. The things that I guessed...

I'm working on my very last question of the last exam of the last class for my corespondents high school program. Almost done! But I need help on this one. I've spent too much time on it already but I still don't know how to answer it. Homework Statement "Complete each equation. Classify...

I know all about the nuclear Boy Scout. And I never suggested anyone build a fission reactor or take apart thousands of smoke detectors. Obviously, that is the first thing people thought of when the OP said he wanted to build a nuclear reactor. I would discourage anyone from doing what the...

If it is illegal (a fusor), then apparently nobody cares, considering I have recently read about a teenager who built a fusor being profiled in popular science or mechanics. If it was a bust your door down offense then I doubt they would have published the article and not mentioned his arrest as...

What about a fusor? Those can produce neutrons and plenty of x-rays and I don't think they are illiegal... The construction of a farnsworth fusor wouldn't be absurd and can achieve nuclear fusion (even better than fission!). A hand full of amateurs have successfully built working (fusing)...

Ok, so are saying that nitrogen can have whatever oxidation # (+/-) that you can write? From what I have found on the internet hydrogen would take a +1 state when it bonds with nonmetals, and a -1 state when it bonds with metals. Also I found on a site this rule "In Binary Compounds, the...

Ok, but I don't see why the oxidation # for nitrogen is stated as +3 in the NO2 molecule (I’m not talking about my NO2 Ion here!) as webelements.com says. With oxygen being fixed at -2 as you say... that would mean, having 2 oxygen’s, that nitrogen would have to be +4 in order to give an overall...

I have a few more questions... for e. -2 makes sense but how is that "allowed" given that there is only +/- in front of the 3 but not the 2 in the above list of oxidation states? Also, I was looking at this page: http://www.webelements.com/webelements/compounds/text/N/N1O2-10102440.html" and...

Thanks for the link. I guess my + and - signs should be in front of the numbers for charge. And yes I'm talking about the oxidation state of N for a. In a. if the 3 hydrogen’s are +1 then N would have to be -3 to make it equal to 0... Makes sense. But cheechnchong and 3trQN, why do...

So... For a. N has an oxidation of 3-? I guess I was thinking of the 1- hydride ion giving N a 3+, how would I know which one in the future? With e. are you saying it should be -4? Because I thought that wouldn't be possible (only 3-, 3+, 5+). I figured it was 3+ because the oxidation # for N...

I worked on this problem for quite a while last night and I'm not at all sure if my answers are correct. This is the problem I’ve been given: I know nitrogen exists in the 3-, 3+ and 5+ oxidation states. I would think that they would give me at least one of each. I'm REALLY not sure about b...

What kind of question is that? It says right at the beginning of the example. It's not like I can't read. I'm working on replying to the other stuff...

They are trying to prove that the statement is true for any integer greater then or equal to the starting value of 1.

In question three I was talking about the part of the problem(s) where there is a bunch of numbers being added together and then it has the … part and then the rest of the evil problem follows. So in example 1 in my textbook I’m talking about this part: 1^2 + 2^2 + 3^2 + …+n^2= so, everything...