Recent content by Alex75

Thank you so much I had gotten that angle on my own but it was mear accident I'm glad I was able to confirm with someone who knows something. Thank you again gleem

So for a coifficent of fiction being .6 between the wood chips and the steel slide I would have to angle it at a slope greater than 30.96 (i. E. 31°) in order for the force of gravity acting upon them would be great enough to overcome the static friction generated by the chips

30.96°

So then °=tan^-1(u) ?

OK I got that far on my own here's where the five years since when I last took physics becomes noticeable how do you isolate the angle from both triginomic functions

So mgsin°=umgcos° would be the equation I would have to evaluate and isolate °?

Wouldn't the normal force be N=mgcos°

I believe that was what we ended up doing in physics class to determine at what angle a car's tires would loose friction between the road surface

Vaguely

None really outside college physics when I was a senior I have always had a love for science and physics though which is way I am attempting to educate myself on what I still need to learn and refresh what I already know

Ff=un Ff is frictional force U is the coifficent of friction N is normal force

That was the equation I found when reshuching frictional forces

No I am trying to determine the minimum angle the slide needs to be placed at so the chips accelerate down the slide. I.e. when the force from gravity is enough to overcome the static friction of the chips

Where m is mass G is acceleration of gravity ° is the angle of the steel slide N is normal force applied to object

Mgsin°=n