Recent content by alexas

The problem is: ((x^3)+x)/(x-1) And i need to break it into partial fractions... I tried long division and got: ((x^2) +x ) But the book gives me the answer of: (x^2)+x+2+(2/(x-1)) Any help would be very much appreciated, thanks.

Yes, so that it moves the sled.

huh?

So we know N is equal to: 537.25N But, how are we supposed to find μ?

N = mg - Fsin(Θ) ?

Ff = μFN or Ff = μmg ?

I'm a little confused on how to proceed. I get what your talking about with the object not accelerating in the y-direction, but i don't understand why we need to factor it in still? I mean i know we're pulling it at an angle so there is a Y component in the Force. I guess I'm just a little...

I was thinking of using the formula of: Fy = MAy and Fx = MAx But when i solve that out I am getting the acceleration as basically Ay = sin(22) Ax = cos(22) Which doesn't seem to be correct to me?

The force i am pulling in the y direction would be: 21.35 N Down: 558.6 <<<<<<< isn't this irrelevant since we are moving in the x direction or does the angle make it nessecary for us to know this? The force i am pulling in the right x direction is: 52.84 The force of friction going to the...

Homework Statement It's a snowy day and you're pulling a friend along a level road on a sled. You've both been taking physics, so she asks what you think the coefficient of friction between the sled and the snow is. You've been walking at a steady 1.5 m/s, and the rope pulls up on the sled at...

That is what frustrates me the most. haha It always seems fairly simple once you know all the steps to a problem.

And for the second part basically following the same methods from before, the correct answer is: 5.16

Got it! I used: Vf = final velocity, which we are trying to find Vi = initial velocity, which is 0? a = 6.67m/s X = 1.3m (vf^2) = Vi + 2aX Anyways after a bit of math the final velocity it reaches when it is at 1.3m is: 4.16 m/s Which by the way is correct. However, i was supposed to give the...

I used 5.18N as the netforce for my calculations earlier, now that i used 10.18N as my netforce my acceleration should be correct since it is: 6.78 m/(s^2) ?

Alright so if that's the case... Acceleration would equal 3.92 (m/(s^2) correct?