I think you are using the result to prove the question .
you mentioned that t is closed and bounded,then processing to prove in the way T is bounded and closed...
If you using S instead of T , your prove still hold.
"Now consider an open cover of T. Then add to that cover the open set V:=R\T...
Thank you.
I think I need some times to understand the last step" Of that subcover, keeping only the U_i's (that is to say, removing V if it in a member of the subcover)"
I need to prove every every open cover of T has a finite subcover.
My version of Heine-Borel theorem is every open cover of a closed interval has a finite subcover.
It is easy to prove if it is a closed interval. I mean like [a,b]
not a interval like T.
I am studying Heine-Borel theorem.
I finally get the sense of this theorem after i read a lots posts here.
But I found a question posted by Rach3
why for S={1,1/2,1/3……} there is no subcollection of it is a cover of S
but every open cover of T={0,1,1/2,1/3……} has a finite subcover?
let me post the whole question
Suppose that f is an entire function such that f(z) = f(z + 2π ) and f(z) = f(z + 2π i)
for all z belong to C. Use Liouville's theorem to show that f is constant.
Hint: Consider the restriction of f to the square {z = x + iy : 0 <x < 2π ; 0 < y <2π }
A question about how find the canonical forms over R and C.
An example, given a quadratic form,q(x,y,z)=x^2 + 2xy + 4yz + z^2
find the canonical forms over R and C.
First step,i get the matrix 1 2^0.5 0
2^0.5 0 2...
For an odd prime number p let Fp be the field with p elements, ie. the integers {0...,p-1} with addition and multiplication defined modulo p. How many quadratic forms are there on the vector space Fp^n
I don even know how to start this question
Why do we calculate the gradient vectors of the surfaces? What is the geometrical meaning of gradient vector? I think I should calculate the normals of two surfaces and get the cross product of two normals, because the vector of the intersection curve is perpendicular to both of the normals..