Recent content by amadinger

You're very welcome! Are you all set?

Interesting question. I'm not sure about the answer, but I would think 'yes' if there were no interference on the vertical line. I would think there would be some, but can't confirm. That's the question you'd want to answer. As for your error range, that is a much more complicated question...

Good catch! I've just confirmed that your values are correct in post #7 above, ignore my reported values. I've found a great video on the matter, and I can confirm you've got it! Check it out here...

Continued: I'm now taking the measurements to the points, and am getting (in mm), with P1 being the top nodal point and P2 being the bottom anodal point, as you said: P1S1: 36.6 P1S2: 39.6 P2S1: 44.6 P2S2: 33.8 Some consistent, some not. The wavelength I found should make the largest...

Two things I can tell you right now, is that you're right on ii) and wrong on i). I've uploaded the image you attached to SketchUp (basic CAD) and scaled it so that I can digitally measure the picture. ii) Yes, it appears the distance between centers is 13mm. i) You're right on the...

This page illustrates what Jbriggs and I are talking about, vector components. It's a very useful and fundamental physics concept. You will see it again and again, and I recommend taking the time to learn it now. I also recommend searching YouTube for "vector components."...

Jaime, I'm having difficulty understanding where you are getting the numbers. Where points 1 and 2 given? How are you calculating i) and ii)? Is there a scale on a picture you are using? Perhaps a 3rd party article can help illuminate the matter...

This is great advice so far! While you could do vector addition by creating a triangle using the 215km W, 85km SW, and a hypotenuse connecting the origin to the SW tip, this could be tricky without CAD or unneeded trig functions. I also recommend breaking up the SW vector into its S and W...

Have I got it? I think I've got a handle now on how to choose a motor. Is this the correct mindset? Please let me know if I've got it or not. Also, if anyone can point me towards a similar problem with a known solution, I'd love to practice. Thanks again for everyone who has helped me...

A-ha! That makes sense. Thank you. However, I see that since the rollers are directly below the loads (person, camera) it makes sense that would mark the distance from the axis of rotation for calculating rotational friction. However, what if the rollers were not right below them? What if...

I think everything I posted above is right, but I've been lead to another question while returning to the original problem. The loads (man and camera) are perpendicular to the rotation of the motor. Will these loads only translate into in-plane friction that the motor has to overcome and...

Eureka! You guys are awesome. I think I've got a handle on it now. 1. F=ma to T=I(alpha): If there is no load, to keep constant w, input T has to equal resistive f. 2. To accelerate w to a higher w, just use T=I(alpha), considering any friction or aerodynamic forces. 3. Same for if there is...

Dear PF, This is my first post, so please pardon any faux pas. I've had some difficulty wrapping my head around the concept of torque. I have taken multiple classes on dynamics, statics, etc. I understand it theoretically, but not practically. A friend presented me with this problem...