Recent content by amalak
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Numerical boundary conditions for wide approximation finite difference
Thank you very much for your response. That method seems to make more sense, I think, but I've been instructed to use U-1 and UN+1, but thank you again.- amalak
- Post #3
- Forum: MATLAB, Maple, Mathematica, LaTeX
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Numerical boundary conditions for wide approximation finite difference
Hi, I have to use a wide 5 point stencil to solve a problem to fourth order accuracy. In particular, the one I'm using is: u'' = -f(x + 2h) + 16f(x + h) - 30f(x) + 16f(x - h) - f(x - 2h) / 12h2 or when discretized u'' = -Uj-2 + 16Uj-1 -30Uj + 16Uj+1 -Uj+2 / 12h2 In addition to...- amalak
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- Approximation Boundary Boundary conditions Conditions Difference Finite Finite difference Numerical
- Replies: 3
- Forum: MATLAB, Maple, Mathematica, LaTeX
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Fluid mechanics book recommendation for new grad
Hey all, I'm a Math major (most of my coursework was in PDEs) and just got accepted into Grad school (yay) for Mechanical Engineering. I need to be very familiar with fluid mechanics and have about 5 months to do so. Trouble is, the last fluid mechanics course I took was about 3-4 years ago...- amalak
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- Book Book recommendation Fluid Fluid mechanics Grad Mechanics Recommendation
- Replies: 4
- Forum: Mechanical Engineering
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Undergrad How to Perform Pairwise Comparisons with Limited Data?
Hi there, If I have 5 numbers that represent the area of a forest from 5 separate years, is it possible to yield 4 pairwise comparisons? I would like to know if the change in area is significant from year to year, but cannot figure out which statistical test to use since I only have one...- amalak
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- Replies: 1
- Forum: Set Theory, Logic, Probability, Statistics
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Square root of negative complex exponential
So in this case, the correct θ is not \pi/3 ? Since, we're trying to solve \theta/2 , wouldn't (2\pi/3)/2 = \pi/3 be in our desired range? Also, how would I handle the -1 in this case if that rule is not valid for complex numbers?\ I think I solved this: -e^{(i2\pi)/3} = e^{-i\pi/3} ...- amalak
- Post #4
- Forum: Calculus and Beyond Homework Help
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Square root of negative complex exponential
Homework Statement Solve \sqrt{-e^{(i2\pi)/3}} Homework Equations The Attempt at a Solution I seem to be missing something simple, as I take: \sqrt{-1} = i then, e^{(1/2)*(i2\pi)/3} which comes out as: ie^{i\pi/3} however, the solution is: -ie^{i\pi/3}, and I can't seem to see where...- amalak
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- Complex Complex exponential Exponential Negative Root Square Square root
- Replies: 5
- Forum: Calculus and Beyond Homework Help